How do you solve 2 sin squared theta equals 1?
first divide each side by 2 so you get...
Then make sine ^2(X)=sine(x^2)
SO you get... sine(X^2)=1/2
Then take the sine^-1 of each side it will look like this X^2=sine^-1(1/2)
type the right side into a calc which will give you a gross decimal but it works (0.5235987756)
so now you have
then take the square root of each side to make it linear and you will get X=.7236012546
and that is your answer!!!! make sure to check it on your calculator...I did and it worked
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Not quite correct, I fear. Try this:
Let s = sin θ.
2s2 = 1;
s2 = ½; and
s = ±½√2.
θ = 45°, 135°, 225°, or 315°;
or, if you prefer,
θ = ¼π, ¾π, 1¼π, or 1¾π.